;向0:200-0:23f依次传送 数据0 - 63(3F)
;0000:0200 = 0020:0000
;0000:023f = 0020:003f
;传送0-63，其实一共有64个数据，所以loop次数是64(40H)
assume cs:codesg

codesg segment

	mov ax,0020h
	mov ds,ax
	mov cx,40h
	
	sub bx,bx
l:	mov ds:[bx],bx
	inc bx
	loop l
	
	mov ax,4c00h
	int 21h
codesg ends

end
